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Popular >

xy^'-y=xln(x)

Solution

x y^{^{'}} - y = x ln (x)

Solution

y = \frac{x ln ^{2} ( x )}{2} + c_{1} x

Solution steps

x y^{'} (x) - y = x ln (x)

Solve linear ODE:

y = \frac{x ln ^{2} ( x )}{2} + c_{1} x

y = \frac{x ln ^{2} ( x )}{2} + c_{1} x

Popular Examples

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(x^{2} + y^{2}) d x + 6 x y d y = 0

inverse oflaplace 1/((s^2+4)(s^2-4))inverse laplace

\frac{1}{( s ^{2} + 4 ) ( s ^{2} - 4 )}

integral of 1/((x-5))

\int \frac{1}{( x - 5 )} d x

Frequently Asked Questions (FAQ)

What is the solution for xy^'-y=xln(x) ?
The solution for xy^'-y=xln(x) is y=(xln^2(x))/2+c_{1}x