What is the derivative of 2x^2-3x ?

The derivative of 2x^2-3x is 4x-3

What is the first derivative of 2x^2-3x ?

The first derivative of 2x^2-3x is 4x-3

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\frac{d}{d x} (2 x^{2} - 3 x)

4 x - 3

Solution steps

\frac{d}{d x} (2 x^{2} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

= 4 x - 3

x \to 7 lim (\frac{1}{( x - 7 ) ^{2}})

\frac{d}{d y} (\frac{1}{y} e^{x y} - ln (y^{2}))

x \to - \infty lim (2 x - 3)

\int 3 x^{2} + y^{2} d x

x \to 6 lim (\frac{1}{x})

What is the derivative of 2x^2-3x ?
The derivative of 2x^2-3x is 4x-3
What is the first derivative of 2x^2-3x ?
The first derivative of 2x^2-3x is 4x-3