What is area 5cos(x),5cos(2x),[0,pi] ?

The answer to area 5cos(x),5cos(2x),[0,pi] is (15sqrt(3))/2

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area 5cos(x),5cos(2x),[0,pi]

area

5 cos (x), 5 cos (2 x), [0, π]

\frac{15 3}{2}

Decimal Notation

12.99038 \dots

Solution steps

Apply the area formula:

\int_{0}^{π} ∣ 5 cos (x) - 5 cos (2 x) ∣ d x

Solve

\int_{0}^{π} ∣ 5 cos (x) - 5 cos (2 x) ∣ d x : \frac{15 3}{2}

The area is:

= \frac{15 3}{2}

\int \frac{cos ^{5} ( 3 x )}{sin ^{14} ( 3 x )} d x

\frac{x - 1}{x ^{2}}

sin (\frac{t}{t + 4})

x^{4} - 4 x^{3}

x \to 0 + lim (tan (\frac{1}{x}))

What is area 5cos(x),5cos(2x),[0,pi] ?
The answer to area 5cos(x),5cos(2x),[0,pi] is (15sqrt(3))/2