What is the sum from n=0 to infinity of (1/4)^n ?

The sum from n=0 to infinity of (1/4)^n is 4/3

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sum from n=0 to infinity of (1/4)^n

n = 0 \sum \infty (\frac{1}{4})^{n}

\frac{4}{3}

Solution steps

n = 0 \sum \infty (\frac{1}{4})^{n}

Apply Series Geometric Test:

\frac{4}{3}

= \frac{4}{3}

\frac{\partial}{\partial x} (e^{x y z^{8}})

\frac{\partial}{\partial x} (6 y^{2})

f (x) = (3 x^{2} - 5 x) e^{x}

f (t) = (t^{62} + 3 t + 3) (5 t^{2} + 4)

\frac{d}{d x} (ln (7 x))

What is the sum from n=0 to infinity of (1/4)^n ?
The sum from n=0 to infinity of (1/4)^n is 4/3