What is the (sin(x)sin(2x)sin(3x))^' ?

The (sin(x)sin(2x)sin(3x))^' is cos(x)sin(2x)sin(3x)+(cos(2x)*2sin(3x)+cos(3x)*3sin(2x))sin(x)

What is the first (sin(x)sin(2x)sin(3x))^' ?

The first (sin(x)sin(2x)sin(3x))^' is cos(x)sin(2x)sin(3x)+(cos(2x)*2sin(3x)+cos(3x)*3sin(2x))sin(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(sin (x) sin (2 x) sin (3 x))^{^{'}}

cos (x) sin (2 x) sin (3 x) + (cos (2 x) \cdot 2 sin (3 x) + cos (3 x) \cdot 3 sin (2 x)) sin (x)

Solution steps

(sin (x) sin (2 x) sin (3 x))^{'}

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sin (x), g = sin (2 x) sin (3 x)

= (sin (x))^{^{'}} sin (2 x) sin (3 x) + (sin (2 x) sin (3 x))^{^{'}} sin (x)

(sin (x))^{'} = cos (x)

(sin (2 x) sin (3 x))^{'} = cos (2 x) \cdot 2 sin (3 x) + cos (3 x) \cdot 3 sin (2 x)

= cos (x) sin (2 x) sin (3 x) + (cos (2 x) \cdot 2 sin (3 x) + cos (3 x) \cdot 3 sin (2 x)) sin (x)

y = e^{x} sin (2 x)

x \to 0 + lim (x ln (sin (x)))

\int \frac{1}{5 x - 2} d x

\int \frac{1}{( 1 + u ) ^{2}} d u

\frac{d r}{d θ} = 8 (cos (\frac{θ}{3}))^{3}

What is the (sin(x)sin(2x)sin(3x))^' ?
The (sin(x)sin(2x)sin(3x))^' is cos(x)sin(2x)sin(3x)+(cos(2x)*2sin(3x)+cos(3x)*3sin(2x))sin(x)
What is the first (sin(x)sin(2x)sin(3x))^' ?
The first (sin(x)sin(2x)sin(3x))^' is cos(x)sin(2x)sin(3x)+(cos(2x)*2sin(3x)+cos(3x)*3sin(2x))sin(x)