What is the derivative of (4x-1^2) ?

The derivative of (4x-1^2) is 8(4x-1)

What is the first derivative of (4x-1^2) ?

The first derivative of (4x-1^2) is 8(4x-1)

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\frac{d}{d x} ((4 x - 1)^{2})

8 (4 x - 1)

Solution steps

\frac{d}{d x} ((4 x - 1)^{2})

Apply the chain rule:

2 (4 x - 1) \frac{d}{d x} (4 x - 1)

= 2 (4 x - 1) \frac{d}{d x} (4 x - 1)

\frac{d}{d x} (4 x - 1) = 4

= 2 (4 x - 1) \cdot 4

Simplify

= 8 (4 x - 1)

y = x^{2}, y = 2 x^{2} - 4 x, y = 0

\int \frac{x ^{2}}{( x ^{2} + 8 ) ^{\frac{3}{2}}} d x

\frac{d r}{d θ} = π

x^{3} - 8 x

\int 18 x^{\frac{1}{2}} d x

What is the derivative of (4x-1^2) ?
The derivative of (4x-1^2) is 8(4x-1)
What is the first derivative of (4x-1^2) ?
The first derivative of (4x-1^2) is 8(4x-1)