What is the solution for y^'=(x-2)/(y+1) ?

The solution for y^'=(x-2)/(y+1) is y=-1+sqrt(x^2-4x+c_{1)+1},y=-sqrt(x^2-4x+c_{1)+1}-1

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y^'=(x-2)/(y+1)

y^{^{'}} = \frac{x - 2}{y + 1}

y = - 1 + x^{2} - 4 x + c_{1} + 1, y = - x^{2} - 4 x + c_{1} + 1 - 1

Solution steps

y^{'} (x) = \frac{x - 2}{y + 1}

Solve separable ODE:

y = - 1 + x^{2} - 4 x + c_{1} + 1, y = - x^{2} - 4 x + c_{1} + 1 - 1

y = - 1 + x^{2} - 4 x + c_{1} + 1, y = - x^{2} - 4 x + c_{1} + 1 - 1

\int - ∣ x ∣^{2} d x

\int_{0}^{1} 4 ln (x) d x

\frac{d}{d x} (\frac{sin ^{2} ( x )}{2})

\frac{d}{d x} (\frac{5}{4 x}) - \frac{7}{4}

\int \frac{( arctan ( x ) ) ^{3}}{1 + x ^{2}} d x

What is the solution for y^'=(x-2)/(y+1) ?
The solution for y^'=(x-2)/(y+1) is y=-1+sqrt(x^2-4x+c_{1)+1},y=-sqrt(x^2-4x+c_{1)+1}-1