What is the integral of sec(38w)tan(38w) ?

The integral of sec(38w)tan(38w) is 1/38 sec(38w)+C

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integral of sec(38w)tan(38w)

\int sec (38 w) tan (38 w) d w

\frac{1}{38} sec (38 w) + C

Solution steps

\int sec (38 w) tan (38 w) d w

Apply u-substitution

: \int \frac{1}{38} d u

= \int \frac{1}{38} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{38} u

Substitute back

u = sec (38 w)

= \frac{1}{38} sec (38 w)

Add a constant to the solution

= \frac{1}{38} sec (38 w) + C

x \to 1 lim (∣ x - 2 ∣)

\int tan (x) sec^{3} (x) d x

\int \frac{x}{x + d} d x

\frac{\partial}{\partial x} (x^{3} - 2 x y + y^{2} + 3)

y^{^{'''}} = 0

What is the integral of sec(38w)tan(38w) ?
The integral of sec(38w)tan(38w) is 1/38 sec(38w)+C