What is the derivative of f(x)=sqrt(1+8x) ?

The derivative of f(x)=sqrt(1+8x) is 4/(sqrt(1+8x))

What is the first derivative of f(x)=sqrt(1+8x) ?

The first derivative of f(x)=sqrt(1+8x) is 4/(sqrt(1+8x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = 1 + 8 x

\frac{4}{1 + 8 x}

Solution steps

\frac{d}{d x} (1 + 8 x)

Apply the chain rule:

\frac{1}{2 1 + 8 x} \frac{d}{d x} (1 + 8 x)

= \frac{1}{2 1 + 8 x} \frac{d}{d x} (1 + 8 x)

\frac{d}{d x} (1 + 8 x) = 8

= \frac{1}{2 1 + 8 x} \cdot 8

Simplify

\frac{1}{2 1 + 8 x} \cdot 8 : \frac{4}{1 + 8 x}

= \frac{4}{1 + 8 x}

(1 + x^{4})^{\frac{2}{3}}

\frac{d}{d x} (\frac{( 5 x - 3 )}{( 4 x - \frac{3}{x} )})

\frac{\partial}{\partial x} (y (- 14 x - 4 y + 1))

\int x (x^{2} + 3)^{2} d x

\int \frac{2}{x ^{\frac{1}{2}}} d x

What is the derivative of f(x)=sqrt(1+8x) ?
The derivative of f(x)=sqrt(1+8x) is 4/(sqrt(1+8x))
What is the first derivative of f(x)=sqrt(1+8x) ?
The first derivative of f(x)=sqrt(1+8x) is 4/(sqrt(1+8x))