What is the integral from-10 to 10 of (x^2+x) ?

The integral from-10 to 10 of (x^2+x) is 2000/3

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integral from-10 to 10 of (x^2+x)

\int_{- 10}^{10} (x^{2} + x) d x

\frac{2000}{3}

Decimal Notation

666.66666 \dots

Solution steps

\int_{- 10}^{10} x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 10}^{10} x^{2} d x + \int_{- 10}^{10} x d x

\int_{- 10}^{10} x^{2} d x = \frac{2000}{3}

\int_{- 10}^{10} x d x = 0

= \frac{2000}{3} + 0

Simplify

= \frac{2000}{3}

\frac{d}{d x} (x (1 - 2 x)^{3})

f (x) = 8 x - 3 x^{2}

\int_{- 1}^{2} \frac{1}{x ^{5}} d x

- \frac{4}{x ^{3}}

\int 2 (x + y) d x

What is the integral from-10 to 10 of (x^2+x) ?
The integral from-10 to 10 of (x^2+x) is 2000/3