What is the integral from-2 to 2 of 4^x ?

The integral from-2 to 2 of 4^x is (255)/(32ln(2))

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integral from-2 to 2 of 4^x

\int_{- 2}^{2} 4^{x} d x

\frac{255}{32 ln ( 2 )}

Decimal Notation

11.49647 \dots

Solution steps

\int_{- 2}^{2} 4^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{4 ^{x}}{ln ( 4 )}]_{- 2}^{2}

\frac{4 ^{x}}{ln ( 4 )} = \frac{2 ^{2 x - 1}}{ln ( 2 )}

= [\frac{2 ^{2 x - 1}}{ln ( 2 )}]_{- 2}^{2}

Compute the boundaries:

\frac{255}{32 ln ( 2 )}

= \frac{255}{32 ln ( 2 )}

\frac{( d y )}{( d x )} = 8 x^{(3)} + 6 x^{(2)}

15 x ln (4 x)

\int \frac{8}{5 ^{3 x}} d x

\int \frac{x ^{2} + 12 x + 12}{x ( x ^{2} - 4 )} d x

\frac{d}{d x} (\frac{8 x ^{2} + 6 x + 6}{x})

What is the integral from-2 to 2 of 4^x ?
The integral from-2 to 2 of 4^x is (255)/(32ln(2))