What is the tangent of f(x)=(4x+5)(5x-1),\at x=3 ?

The tangent of f(x)=(4x+5)(5x-1),\at x=3 is y=141x-185

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tangent of f(x)=(4x+5)(5x-1),\at x=3

tangent of

f (x) = (4 x + 5) (5 x - 1), at x = 3

y = 141 x - 185

Solution steps

Find the tangent point:

(3, 238)

Find the slope of

f (x) = (4 x + 5) (5 x - 1) : \frac{df ( x )}{d x} = 40 x + 21

Compute the slope of

f (x) = (4 x + 5) (5 x - 1)

x = 3 : m = 141

Find the line with slope m=

141

and passing through

(3, 238) : y = 141 x - 185

y = 141 x - 185

\int 25 e^{- 5 x} sin (5 x) d x

\int - \frac{x}{1 - x ^{2}} d x

\frac{d}{d x} (x, (x))

x \to - 2 lim (x^{2} - a)

What is the tangent of f(x)=(4x+5)(5x-1),\at x=3 ?
The tangent of f(x)=(4x+5)(5x-1),\at x=3 is y=141x-185