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Popular >

y^'=(-2xy)/(1+x^2)

Solution

y^{^{'}} = \frac{- 2 x y}{1 + x ^{2}}

Solution

y = \frac{c _{1}}{1 + x ^{2}}

Solution steps

y^{'} (x) = \frac{- 2 x y}{1 + x ^{2}}

Solve separable ODE:

y = \frac{c _{1}}{1 + x ^{2}}

y = \frac{c _{1}}{1 + x ^{2}}

Popular Examples

(\partial)/(\partial x)(42y^8x^5-30y^7x^4)

\frac{\partial}{\partial x} (42 y^{8} x^{5} - 30 y^{7} x^{4})

derivative of cos(2arctan(x/2))derivative of

cos (2 arctan (\frac{x}{2}))

integral of (u^2)/(sqrt(u^2-8u))

\int \frac{u ^{2}}{u ^{2} - 8 u} d u

derivative of x^{1/3}(x+4)

\frac{d}{d x} (x^{\frac{1}{3}} (x + 4))

derivative of 2/(1+3x+x^2)derivative of

\frac{2}{1 + 3 x + x ^{2}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=(-2xy)/(1+x^2) ?
The solution for y^'=(-2xy)/(1+x^2) is y=(c_{1})/(1+x^2)