What is the solution for (dy}{dx}=\frac{y^3)/x ,y(1)=1 ?

The solution for (dy}{dx}=\frac{y^3)/x ,y(1)=1 is y=sqrt(-1/(2ln(x)-1))

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(dy}{dx}=\frac{y^3)/x ,y(1)=1

\frac{d y}{d x} = \frac{y ^{3}}{x}, y (1) = 1

y = - \frac{1}{2 ln ( x ) - 1}

Solution steps

\frac{d y}{d x} = \frac{y ^{3}}{x}

Solve separable ODE:

y = - \frac{1}{2 ln ( x ) - 1}

y = - \frac{1}{2 ln ( x ) - 1}

\int \frac{x ^{2} - 5 x + 9}{x ^{2} - 5 x + 6} d x

\frac{\partial}{\partial x} (x, y, z)

x^{3}, 0, 3

f (x) = \frac{2 ln ( x )}{x}, at x = e

\int \frac{- x}{x ^{2} + y ^{2}} d y

What is the solution for (dy}{dx}=\frac{y^3)/x ,y(1)=1 ?
The solution for (dy}{dx}=\frac{y^3)/x ,y(1)=1 is y=sqrt(-1/(2ln(x)-1))