What is the derivative of 40sqrt(x) ?

The derivative of 40sqrt(x) is (20)/(sqrt(x))

What is the first derivative of 40sqrt(x) ?

The first derivative of 40sqrt(x) is (20)/(sqrt(x))

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\frac{d}{d x} (40 x)

\frac{20}{x}

Solution steps

\frac{d}{d x} (40 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 40 \frac{d}{d x} (x)

Apply radical rule:

a = a^{\frac{1}{2}}

= 40 \frac{d}{d x} (x^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 40 \cdot \frac{1}{2} x^{\frac{1}{2} - 1}

Simplify

40 \cdot \frac{1}{2} x^{\frac{1}{2} - 1} : \frac{20}{x}

= \frac{20}{x}

x \to - 2 lim (3 x - 1)

\int \frac{ln ( x ^{2} + 1 )}{x ^{3}} d x

\frac{\partial}{\partial x} (x^{0.25} Y (x)^{0.5})

2 x^{2} - x - 3

\frac{1}{( s ^{2} + 0.2 s + 1 ) s}

What is the derivative of 40sqrt(x) ?
The derivative of 40sqrt(x) is (20)/(sqrt(x))
What is the first derivative of 40sqrt(x) ?
The first derivative of 40sqrt(x) is (20)/(sqrt(x))