What is the integral of xtan^2(x) ?

The integral of xtan^2(x) is -x^2+xtan(x)+(x^2)/2+ln|cos(x)|+C

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integral of xtan^2(x)

\int x tan^{2} (x) d x

- x^{2} + x tan (x) + \frac{x ^{2}}{2} + ln ∣ cos (x) ∣ + C

Solution steps

\int x tan^{2} (x) d x

Apply Integration By Parts

: x (- x + tan (x)) - \int - x + tan (x) d x

= x (- x + tan (x)) - \int - x + tan (x) d x

\int - x + tan (x) d x = - \frac{x ^{2}}{2} - ln ∣ cos (x) ∣

= x (- x + tan (x)) - (- \frac{x ^{2}}{2} - ln ∣ cos (x) ∣)

Simplify

x (- x + tan (x)) - (- \frac{x ^{2}}{2} - ln ∣ cos (x) ∣) : - x^{2} + x tan (x) + \frac{x ^{2}}{2} + ln ∣ cos (x) ∣

= - x^{2} + x tan (x) + \frac{x ^{2}}{2} + ln ∣ cos (x) ∣

Add a constant to the solution

= - x^{2} + x tan (x) + \frac{x ^{2}}{2} + ln ∣ cos (x) ∣ + C

(x + 2 y) d x + (2 x - 3 y) d y = 0

f (z) = 8 z^{2} e^{z}

x + 5

\frac{d ^{4} y}{d x ^{4}} - 3 y = 0

y = x, y = ln (x), x = 1, x = 2

What is the integral of xtan^2(x) ?
The integral of xtan^2(x) is -x^2+xtan(x)+(x^2)/2+ln|cos(x)|+C