What is the integral from-2 to 2 of 1/v ?

The integral from-2 to 2 of 1/v is diverges

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integral from-2 to 2 of 1/v

\int_{- 2}^{2} \frac{1}{v} d v

diverges

Solution steps

\int_{- 2}^{2} \frac{1}{v} d v

Find undefined (singularity) points:

v = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 2}^{0} \frac{1}{v} d v + \int_{0}^{2} \frac{1}{v} d v

\int_{- 2}^{0} \frac{1}{v} d v =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

x \to 0 + lim (x^{5 x})

y^{^{''}} - 9 y^{^{'}} + 18 y = e^{e^{- 3 x}}

\int - sin (- x + 2) d x

\int 4 y^{3} x d y

What is the integral from-2 to 2 of 1/v ?
The integral from-2 to 2 of 1/v is diverges