What is (\partial)/(\partial x)(x/(1+y^2)) ?

The answer to (\partial)/(\partial x)(x/(1+y^2)) is 1/(1+y^2)

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(\partial)/(\partial x)(x/(1+y^2))

\frac{\partial}{\partial x} (\frac{x}{1 + y ^{2}})

\frac{1}{1 + y ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{x}{1 + y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{1 + y ^{2}} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= \frac{1}{1 + y ^{2}} \cdot 1

Simplify

= \frac{1}{1 + y ^{2}}

\int \frac{7}{x ^{2} - 2 x} d x

\frac{d}{d t} (3 t e^{- t})

b \to - 3 lim (\frac{b + 1}{b + 3})

y = x^{8} e^{x}

\frac{d}{d x} ((\frac{d x}{d x})^{2})

What is (\partial)/(\partial x)(x/(1+y^2)) ?
The answer to (\partial)/(\partial x)(x/(1+y^2)) is 1/(1+y^2)