What is the tangent of f(x)= 2/(x-2),\at x=4 ?

The tangent of f(x)= 2/(x-2),\at x=4 is y=-1/2 x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 2/(x-2),\at x=4

tangent of

f (x) = \frac{2}{x - 2}, at x = 4

y = - \frac{1}{2} x + 3

Solution steps

Find the tangent point:

(4, 1)

Find the slope of

f (x) = \frac{2}{x - 2} : \frac{df ( x )}{d x} = - \frac{2}{( x - 2 ) ^{2}}

Compute the slope of

f (x) = \frac{2}{x - 2}

x = 4 : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(4, 1) : y = - \frac{1}{2} x + 3

y = - \frac{1}{2} x + 3

x^{2} - 6, - 2 x + 9, - 5, 3

\int 9 sin (9 x) d x

\int \frac{9}{1 + e ^{2 x}} d x

f (x) = \frac{x ^{4}}{cos ( x )}

What is the tangent of f(x)= 2/(x-2),\at x=4 ?
The tangent of f(x)= 2/(x-2),\at x=4 is y=-1/2 x+3