What is implicit (dy)/(dx),6e^{xy}-x=0 ?

The answer to implicit (dy)/(dx),6e^{xy}-x=0 is (dy)/(dx)=(1-6e^{xy}y)/(6e^{xy)x}

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implicit (dy)/(dx),6e^{xy}-x=0

implicit derivative

\frac{d y}{d x}, 6 e^{x y} - x = 0

\frac{d y}{d x} = \frac{1 - 6 e ^{x y} y}{6 e ^{x y} x}

Solution steps

6 e^{x y} - x = 0

Treat

y

y (x)

Differentiate both sides:

6 e^{x y} (y + x \frac{d y}{d x}) - 1 = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{1 - 6 e ^{x y} y}{6 e ^{x y} x}

\frac{d y}{d x} = \frac{1 - 6 e ^{x y} y}{6 e ^{x y} x}

\frac{e ^{x}}{x ^{2} + 14}

\int_{1}^{2} \frac{7}{x ^{3} + 4 x} d x

\frac{\partial}{\partial y} (sin (y) - y sin (x))

\frac{d}{d x} (e^{x x^{2} + 1})

t \to 1 - lim (\frac{2 t}{t ^{2} - 1})

What is implicit (dy)/(dx),6e^{xy}-x=0 ?
The answer to implicit (dy)/(dx),6e^{xy}-x=0 is (dy)/(dx)=(1-6e^{xy}y)/(6e^{xy)x}