What is the derivative of sqrt(2x+8) ?

The derivative of sqrt(2x+8) is 1/(sqrt(2x+8))

What is the first derivative of sqrt(2x+8) ?

The first derivative of sqrt(2x+8) is 1/(sqrt(2x+8))

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derivative of

2 x + 8

\frac{1}{2 x + 8}

Solution steps

\frac{d}{d x} (2 x + 8)

Apply the chain rule:

\frac{1}{2 2 x + 8} \frac{d}{d x} (2 x + 8)

= \frac{1}{2 2 x + 8} \frac{d}{d x} (2 x + 8)

\frac{d}{d x} (2 x + 8) = 2

= \frac{1}{2 2 x + 8} \cdot 2

Simplify

\frac{1}{2 2 x + 8} \cdot 2 : \frac{1}{2 x + 8}

= \frac{1}{2 x + 8}

(0.1) (3.7)

\int 7 cos^{2} (x) tan^{3} (x) d x

\int_{0}^{2} x - 2 d x

x \to 0 lim (\frac{1}{x} cos (\frac{1}{x}))

\frac{d}{d x} (\frac{5}{1 + 5 x})

What is the derivative of sqrt(2x+8) ?
The derivative of sqrt(2x+8) is 1/(sqrt(2x+8))
What is the first derivative of sqrt(2x+8) ?
The first derivative of sqrt(2x+8) is 1/(sqrt(2x+8))