What is the tangent of f(x)=4x^2,\at x=10 ?

The tangent of f(x)=4x^2,\at x=10 is y=80x-400

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=4x^2,\at x=10

tangent of

f (x) = 4 x^{2}, at x = 10

y = 80 x - 400

Solution steps

Find the tangent point:

(10, 400)

Find the slope of

f (x) = 4 x^{2} : \frac{df ( x )}{d x} = 8 x

Compute the slope of

f (x) = 4 x^{2}

x = 10 : m = 80

Find the line with slope m=

80

and passing through

(10, 400) : y = 80 x - 400

y = 80 x - 400

\frac{d}{d x} (1500 x + 3000 (2 x + 3)^{- 1} - 1000)

\frac{d}{d x} (y sin (x))

\int \frac{x ^{8} - 5 x}{x ^{6}} d x

\int 7 cos^{4} (x) d x

\frac{d y}{d t} + e^{t} y = 20 e^{t}

What is the tangent of f(x)=4x^2,\at x=10 ?
The tangent of f(x)=4x^2,\at x=10 is y=80x-400