What is the sum from n=0 to infinity of 1/(13n+42) ?

The sum from n=0 to infinity of 1/(13n+42) is diverges

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sum from n=0 to infinity of 1/(13n+42)

n = 0 \sum \infty \frac{1}{13 n + 42}

diverges

Solution steps

n = 0 \sum \infty \frac{1}{13 n + 42}

Apply Series Integral Test:

diverges

= diverges

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What is the sum from n=0 to infinity of 1/(13n+42) ?
The sum from n=0 to infinity of 1/(13n+42) is diverges