What is the derivative of 3/8 (x^{4/3}-2x^{2/3}) ?

The derivative of 3/8 (x^{4/3}-2x^{2/3}) is (x^{2/3}-1)/(2x^{1/3)}

What is the first derivative of 3/8 (x^{4/3}-2x^{2/3}) ?

The first derivative of 3/8 (x^{4/3}-2x^{2/3}) is (x^{2/3}-1)/(2x^{1/3)}

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\frac{d}{d x} (\frac{3}{8} (x^{\frac{4}{3}} - 2 x^{\frac{2}{3}}))

\frac{x ^{\frac{2}{3}} - 1}{2 x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (\frac{3}{8} (x^{\frac{4}{3}} - 2 x^{\frac{2}{3}}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{3}{8} \frac{d}{d x} (x^{\frac{4}{3}} - 2 x^{\frac{2}{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{3}{8} (\frac{d}{d x} (x^{\frac{4}{3}}) - \frac{d}{d x} (2 x^{\frac{2}{3}}))

\frac{d}{d x} (x^{\frac{4}{3}}) = \frac{4 x ^{\frac{1}{3}}}{3}

\frac{d}{d x} (2 x^{\frac{2}{3}}) = \frac{4}{3 x ^{\frac{1}{3}}}

= \frac{3}{8} (\frac{4 x ^{\frac{1}{3}}}{3} - \frac{4}{3 x ^{\frac{1}{3}}})

Simplify

\frac{3}{8} (\frac{4 x ^{\frac{1}{3}}}{3} - \frac{4}{3 x ^{\frac{1}{3}}}) : \frac{x ^{\frac{2}{3}} - 1}{2 x ^{\frac{1}{3}}}

= \frac{x ^{\frac{2}{3}} - 1}{2 x ^{\frac{1}{3}}}

\frac{d}{d x} (- sin (5 π x) \cdot 5 π)

\frac{d}{d x} ((x^{3} + 2)^{2} (x^{4} + 4)^{4})

y^{^{'}} (t) = 0.3 y \cdot (1 - \frac{y}{2500}) - \frac{y}{4}, y (0) = 600

\int \frac{tan ^{3} ( x )}{2} d x

\frac{\partial}{\partial x} (cos (- 5 x - 6 y))

What is the derivative of 3/8 (x^{4/3}-2x^{2/3}) ?
The derivative of 3/8 (x^{4/3}-2x^{2/3}) is (x^{2/3}-1)/(2x^{1/3)}
What is the first derivative of 3/8 (x^{4/3}-2x^{2/3}) ?
The first derivative of 3/8 (x^{4/3}-2x^{2/3}) is (x^{2/3}-1)/(2x^{1/3)}