What is the d/(dn)(sin(n^3m)) ?

The d/(dn)(sin(n^3m)) is cos(n^3m)*3mn^2

What is the first d/(dn)(sin(n^3m)) ?

The first d/(dn)(sin(n^3m)) is cos(n^3m)*3mn^2

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\frac{d}{d n} (sin (n^{3} m))

cos (n^{3} m) \cdot 3 m n^{2}

Solution steps

\frac{d}{d n} (sin (n^{3} m))

Apply the chain rule:

cos (n^{3} m) \frac{d}{d n} (n^{3} m)

= cos (n^{3} m) \frac{d}{d n} (n^{3} m)

\frac{d}{d n} (n^{3} m) = 3 m n^{2}

= cos (n^{3} m) \cdot 3 m n^{2}

\int \frac{1}{1 - 2 x} d x

\int (x e^{x}) d x

\int csc (8 x) cot (8 x) d x

ln (4 x)

What is the d/(dn)(sin(n^3m)) ?
The d/(dn)(sin(n^3m)) is cos(n^3m)*3mn^2
What is the first d/(dn)(sin(n^3m)) ?
The first d/(dn)(sin(n^3m)) is cos(n^3m)*3mn^2