What is the integral from 1 to 9 of 9x^2 ?

The integral from 1 to 9 of 9x^2 is 2184

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integral from 1 to 9 of 9x^2

\int_{1}^{9} 9 x^{2} d x

2184

Solution steps

\int_{1}^{9} 9 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{1}^{9} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{9}

= 9 [\frac{x ^{3}}{3}]_{1}^{9}

Compute the boundaries:

\frac{728}{3}

= 9 \cdot \frac{728}{3}

Simplify

= 2184

y = \frac{88 t}{99 t - 88}

\frac{d}{d x} (x - y^{2})

\frac{d}{d x} (x^{\frac{2}{3}} (x - 2))

y^{^{'}} = \frac{3 x ^{2} + y ^{2}}{x y}

ln (sec (2 x) + tan (2 x))

What is the integral from 1 to 9 of 9x^2 ?
The integral from 1 to 9 of 9x^2 is 2184