What is the derivative of (x^4+3x^2-2^5) ?

The derivative of (x^4+3x^2-2^5) is 5(x^4+3x^2-2)^4(4x^3+6x)

What is the first derivative of (x^4+3x^2-2^5) ?

The first derivative of (x^4+3x^2-2^5) is 5(x^4+3x^2-2)^4(4x^3+6x)

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\frac{d}{d x} ((x^{4} + 3 x^{2} - 2)^{5})

5 (x^{4} + 3 x^{2} - 2)^{4} (4 x^{3} + 6 x)

Solution steps

\frac{d}{d x} ((x^{4} + 3 x^{2} - 2)^{5})

Apply the chain rule:

5 (x^{4} + 3 x^{2} - 2)^{4} \frac{d}{d x} (x^{4} + 3 x^{2} - 2)

= 5 (x^{4} + 3 x^{2} - 2)^{4} \frac{d}{d x} (x^{4} + 3 x^{2} - 2)

\frac{d}{d x} (x^{4} + 3 x^{2} - 2) = 4 x^{3} + 6 x

= 5 (x^{4} + 3 x^{2} - 2)^{4} (4 x^{3} + 6 x)

\int \frac{( 3 y - 8 )}{y ^{2} - 4 y - 5} d y

\int \frac{1}{( 3 x + 7 ) ^{2}} d x

\frac{s ^{2}}{s - 1}

e^{- 13 x}

\frac{d y}{d x} = \frac{( x ^{2} - 3 y ^{2} )}{2 x y}

What is the derivative of (x^4+3x^2-2^5) ?
The derivative of (x^4+3x^2-2^5) is 5(x^4+3x^2-2)^4(4x^3+6x)
What is the first derivative of (x^4+3x^2-2^5) ?
The first derivative of (x^4+3x^2-2^5) is 5(x^4+3x^2-2)^4(4x^3+6x)