What is the integral from 0 to 1 of xsin(x) ?

The integral from 0 to 1 of xsin(x) is sin(1)-cos(1)

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integral from 0 to 1 of xsin(x)

\int_{0}^{1} x sin (x) d x

sin (1) - cos (1)

Decimal Notation

0.30116 \dots

Solution steps

\int_{0}^{1} x sin (x) d x

Apply Integration By Parts

: [- x cos (x) - \int - cos (x) d x]_{0}^{1}

= [- x cos (x) - \int - cos (x) d x]_{0}^{1}

\int - cos (x) d x = - sin (x)

= [- x cos (x) - (- sin (x))]_{0}^{1}

Simplify

= [- x cos (x) + sin (x)]_{0}^{1}

Compute the boundaries:

sin (1) - cos (1)

= sin (1) - cos (1)

x \to - 1 lim (\frac{2 x + 8}{x})

\frac{d}{d x} (60 e^{- 4.8 x} sin (16 x))

x = y^{2}, x = 9

\int e^{- c x^{2}} d x

\int \frac{x ^{2}}{( x ^{2} - 8 ^{2} ) ^{\frac{3}{2}}} d x

What is the integral from 0 to 1 of xsin(x) ?
The integral from 0 to 1 of xsin(x) is sin(1)-cos(1)