What is the integral of (x^2-7x+2) ?

The integral of (x^2-7x+2) is (x^3)/3-(7x^2)/2+2x+C

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integral of (x^2-7x+2)

\int (x^{2} - 7 x + 2) d x

\frac{x ^{3}}{3} - \frac{7 x ^{2}}{2} + 2 x + C

Solution steps

\int x^{2} - 7 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 7 x d x + \int 2 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 7 x d x = \frac{7 x ^{2}}{2}

\int 2 d x = 2 x

= \frac{x ^{3}}{3} - \frac{7 x ^{2}}{2} + 2 x

Add a constant to the solution

= \frac{x ^{3}}{3} - \frac{7 x ^{2}}{2} + 2 x + C

y = e^{5 x}, at x = \frac{1}{5} ln (5)

\int 5 sin^{3} (x co) s^{7} x d x

\frac{d}{d x} (arccsc (4 x^{2} + 1))

\int (5 x^{4} + \frac{x}{7}) d x

\frac{d y}{d x} + y + 2 cos (x) = 0

What is the integral of (x^2-7x+2) ?
The integral of (x^2-7x+2) is (x^3)/3-(7x^2)/2+2x+C