What is the derivative of ln(2^x) ?

The derivative of ln(2^x) is ln(2)

What is the first derivative of ln(2^x) ?

The first derivative of ln(2^x) is ln(2)

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derivative of

ln (2^{x})

ln (2)

Solution steps

\frac{d}{d x} (ln (2^{x}))

Simplify

ln (2^{x}) : ln (2) x

= \frac{d}{d x} (ln (2) x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= ln (2) \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= ln (2) \cdot 1

Simplify

= ln (2)

\int \frac{t ^{2}}{1 + t ^{2}} d t

\int 8 x^{3} + \frac{1}{x} d x

\frac{\partial}{\partial y} (e^{7 x e^{y}})

f (x) = 6 x^{3} cot (x)

f (x) = x^{3} 5 - x^{2}, at x = 2

What is the derivative of ln(2^x) ?
The derivative of ln(2^x) is ln(2)
What is the first derivative of ln(2^x) ?
The first derivative of ln(2^x) is ln(2)