What is the limit as x approaches-1 of (f(x))/(x+1) ?

The limit as x approaches-1 of (f(x))/(x+1) is diverges

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limit as x approaches-1 of (f(x))/(x+1)

x \to - 1 lim (\frac{f ( x )}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{f ( x )}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{f ( x )}{x + 1}) = - \infty

x \to - 1 - lim (\frac{f ( x )}{x + 1}) = \infty

= diverges

y^{^{'}} = \frac{- x y ^{2}}{2}

\int \frac{1}{N} d N

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\int e^{x} sin (t - x) d x

\frac{d}{d x} (x^{\frac{5}{4}} + e^{- 3 x})

What is the limit as x approaches-1 of (f(x))/(x+1) ?
The limit as x approaches-1 of (f(x))/(x+1) is diverges