What is the derivative of ln(1+4x) ?

The derivative of ln(1+4x) is 4/(1+4x)

What is the first derivative of ln(1+4x) ?

The first derivative of ln(1+4x) is 4/(1+4x)

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\frac{d}{d x} (ln (1 + 4 x))

\frac{4}{1 + 4 x}

Solution steps

\frac{d}{d x} (ln (1 + 4 x))

Apply the chain rule:

\frac{1}{1 + 4 x} \frac{d}{d x} (1 + 4 x)

= \frac{1}{1 + 4 x} \frac{d}{d x} (1 + 4 x)

\frac{d}{d x} (1 + 4 x) = 4

= \frac{1}{1 + 4 x} \cdot 4

Simplify

\frac{1}{1 + 4 x} \cdot 4 : \frac{4}{1 + 4 x}

= \frac{4}{1 + 4 x}

(- 10, - 8), (- 8, - 16)

\frac{d}{d x} (3 e^{5 x})

x = y^{2}, y = x - 2

x \to 0 lim (∣ x ∣ x)

\int x \cdot x - 1 d x

What is the derivative of ln(1+4x) ?
The derivative of ln(1+4x) is 4/(1+4x)
What is the first derivative of ln(1+4x) ?
The first derivative of ln(1+4x) is 4/(1+4x)