What is the integral from 0 to infinity of-e^{-x} ?

The integral from 0 to infinity of-e^{-x} is -1

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integral from 0 to infinity of-e^{-x}

\int_{0}^{\infty} - e^{- x} d x

- 1

Solution steps

\int_{0}^{\infty} - e^{- x} d x

Compute the indefinite integral:

\int - e^{- x} d x = e^{- x} + C

Compute the boundaries:

\int_{0}^{\infty} - e^{- x} d x = 0 - 1

= 0 - 1

Simplify

= - 1

f (x) = 2 x^{2} + 2 x, at x = - 2

\int_{- 3}^{3} (e^{x} - e^{- x})^{2} d x

\frac{d}{d t} (cos (t) + t sin (t))

ln (\frac{z + \frac{1}{2}}{z})

f (x) = 6 cos (2 x - \frac{π}{3}) + 3 x

What is the integral from 0 to infinity of-e^{-x} ?
The integral from 0 to infinity of-e^{-x} is -1