What is the derivative of 8cos^3(t) ?

The derivative of 8cos^3(t) is -24cos^2(t)sin(t)

What is the first derivative of 8cos^3(t) ?

The first derivative of 8cos^3(t) is -24cos^2(t)sin(t)

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derivative of

8 cos^{3} (t)

- 24 cos^{2} (t) sin (t)

Solution steps

\frac{d}{d t} (8 cos^{3} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d t} (cos^{3} (t))

Apply the chain rule:

3 (cos (t))^{2} \frac{d}{d t} (cos (t))

= 3 (cos (t))^{2} \frac{d}{d t} (cos (t))

\frac{d}{d t} (cos (t)) = - sin (t)

= 8 \cdot 3 (cos (t))^{2} (- sin (t))

Simplify

= - 24 cos^{2} (t) sin (t)

f (x) = \frac{4 x}{( x ^{2} + 1 )}

\int x^{- \frac{1}{4}} d x

\frac{d y}{d x} = 8 x^{3} y - 8 x y

\int 0.04 e^{0.01 x} d x

\int x 2 x d x

What is the derivative of 8cos^3(t) ?
The derivative of 8cos^3(t) is -24cos^2(t)sin(t)
What is the first derivative of 8cos^3(t) ?
The first derivative of 8cos^3(t) is -24cos^2(t)sin(t)