What is the limit as x approaches-4 of x^2cos(5/x) ?

The limit as x approaches-4 of x^2cos(5/x) is 16cos(5/4)

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limit as x approaches-4 of x^2cos(5/x)

x \to - 4 lim (x^{2} cos (\frac{5}{x}))

16 cos (\frac{5}{4})

Decimal Notation

5.04515 \dots

Solution steps

x \to - 4 lim (x^{2} cos (\frac{5}{x}))

Plug in the value

x = - 4

= (- 4)^{2} cos (\frac{5}{- 4})

Simplify

(- 4)^{2} cos (\frac{5}{- 4}) : 16 cos (\frac{5}{4})

= 16 cos (\frac{5}{4})

\int \frac{3 tan ( β ) - 4 cos ^{2} ( β )}{cos ( β )} d β

y = lo g_{7} (x e^{x})

\int \frac{x ^{2} - 5 x + 6}{( 2 x + 1 ) ( x - 2 ) ^{2}} d x

\frac{2 x d y}{d x} = 1 - y^{2}

y = x^{2} - 3, y = 6

What is the limit as x approaches-4 of x^2cos(5/x) ?
The limit as x approaches-4 of x^2cos(5/x) is 16cos(5/4)