What is the sum from n=1 to infinity of sin^n(2) ?

The sum from n=1 to infinity of sin^n(2) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of sin^n(2)

n = 1 \sum \infty sin^{n} (2)

converges

Solution steps

n = 1 \sum \infty sin^{n} (2)

Apply Series Ratio Test:

converges

= converges

\int (x^{2} + 9)^{5} 2 x d x

y = e^{- 5 x}, x \geq 0

x \to 2 lim (4 x - 7)

\int \frac{1}{( z + \frac{1}{2} )} d z

\int \frac{cos ^{5} ( 20 )}{sin ( 20 )} d^{0} dd

What is the sum from n=1 to infinity of sin^n(2) ?
The sum from n=1 to infinity of sin^n(2) is converges