What is the derivative of (3x+1(5x-4)) ?

The derivative of (3x+1(5x-4)) is 30x-7

What is the first derivative of (3x+1(5x-4)) ?

The first derivative of (3x+1(5x-4)) is 30x-7

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\frac{d}{d x} ((3 x + 1) (5 x - 4))

30 x - 7

Solution steps

\frac{d}{d x} ((3 x + 1) (5 x - 4))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 3 x + 1, g = 5 x - 4

= \frac{d}{d x} (3 x + 1) (5 x - 4) + \frac{d}{d x} (5 x - 4) (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

\frac{d}{d x} (5 x - 4) = 5

= 3 (5 x - 4) + 5 (3 x + 1)

Simplify

3 (5 x - 4) + 5 (3 x + 1) : 30 x - 7

= 30 x - 7

\frac{\partial}{\partial x} (cos (z w))

n = 1 \sum \infty \frac{n !}{1 0 ^{n}}

\frac{x ^{4} - 5 x ^{3} + x}{x ^{2}}

\int \frac{12}{r ^{2} + 1} d r

\int \frac{1}{100 + x ^{2}} d x

What is the derivative of (3x+1(5x-4)) ?
The derivative of (3x+1(5x-4)) is 30x-7
What is the first derivative of (3x+1(5x-4)) ?
The first derivative of (3x+1(5x-4)) is 30x-7