What is (\partial)/(\partial x)(x/(9+y)) ?

The answer to (\partial)/(\partial x)(x/(9+y)) is 1/(9+y)

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(\partial)/(\partial x)(x/(9+y))

\frac{\partial}{\partial x} (\frac{x}{9 + y})

\frac{1}{9 + y}

Solution steps

\frac{\partial}{\partial x} (\frac{x}{9 + y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{9 + y} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= \frac{1}{9 + y} \cdot 1

Simplify

= \frac{1}{9 + y}

\int \frac{1}{( x ^{2} - 361 ) ^{\frac{3}{2}}} d x

y = 7 x^{3} - 6 x^{2} - \frac{8}{x}

4 y^{^{''}} - y^{^{'}} + y = 0

y^{^{''}} + 2 y^{^{'}} - y = 10

\frac{d y}{d x} = 1 - 9 y^{2}, y (- 1) = 0

What is (\partial)/(\partial x)(x/(9+y)) ?
The answer to (\partial)/(\partial x)(x/(9+y)) is 1/(9+y)