What is the solution for (dy)/(dx)=3x^2(1+y^2) ?

The solution for (dy)/(dx)=3x^2(1+y^2) is y=tan(x^3+c_{1})

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(dy)/(dx)=3x^2(1+y^2)

\frac{d y}{d x} = 3 x^{2} (1 + y^{2})

y = tan (x^{3} + c_{1})

Solution steps

\frac{d y}{d x} = 3 x^{2} (1 + y^{2})

Solve separable ODE:

y = tan (x^{3} + c_{1})

y = tan (x^{3} + c_{1})

y^{^{'}} = \frac{4 x sec ( \frac{y}{x} ) + y}{x}

y^{^{''}} + π y = 0

\int (cos^{2} (t)) d t

n = 2 \sum \infty sin (\frac{1}{n})

\int_{- π}^{π} x^{2} cos (2 x) d x

What is the solution for (dy)/(dx)=3x^2(1+y^2) ?
The solution for (dy)/(dx)=3x^2(1+y^2) is y=tan(x^3+c_{1})