What is the derivative of 2x^3-15x^2+36x+5 ?

The derivative of 2x^3-15x^2+36x+5 is 6x^2-30x+36

What is the first derivative of 2x^3-15x^2+36x+5 ?

The first derivative of 2x^3-15x^2+36x+5 is 6x^2-30x+36

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\frac{d}{d x} (2 x^{3} - 15 x^{2} + 36 x + 5)

6 x^{2} - 30 x + 36

Solution steps

\frac{d}{d x} (2 x^{3} - 15 x^{2} + 36 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (15 x^{2}) + \frac{d}{d x} (36 x) + \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (15 x^{2}) = 30 x

\frac{d}{d x} (36 x) = 36

\frac{d}{d x} (5) = 0

= 6 x^{2} - 30 x + 36 + 0

Simplify

= 6 x^{2} - 30 x + 36

x^{2} - x, 3 x + 5

\frac{d}{d x} (\frac{( x - 2 ) ^{2}}{4})

2 x^{3} y^{^{'}} = y (y^{2} + 3 x^{2})

\int 6 x + 1 d x

y = - \frac{x ^{2}}{40}, (- 45, - 2)

What is the derivative of 2x^3-15x^2+36x+5 ?
The derivative of 2x^3-15x^2+36x+5 is 6x^2-30x+36
What is the first derivative of 2x^3-15x^2+36x+5 ?
The first derivative of 2x^3-15x^2+36x+5 is 6x^2-30x+36