What is laplacetransform-7(t-4) ?

The answer to laplacetransform-7(t-4) is -7/(s^2)+(28)/s

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laplacetransform-7(t-4)

laplace transform

- 7 (t - 4)

- \frac{7}{s ^{2}} + \frac{28}{s}

Solution steps

L {- 7 (t - 4)}

Expand

- 7 (t - 4) : - 7 t + 28

= L {- 7 t + 28}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= - 7 L {t} + L {28}

L {t} : \frac{1}{s ^{2}}

L {28} : \frac{28}{s}

= - 7 \cdot \frac{1}{s ^{2}} + \frac{28}{s}

Refine

- 7 \frac{1}{s ^{2}} + \frac{28}{s} : - \frac{7}{s ^{2}} + \frac{28}{s}

= - \frac{7}{s ^{2}} + \frac{28}{s}

\frac{d}{d x} (x (2 x + 1)^{5})

\frac{d y}{d x} = 5 y + y^{2}

f (x) = sin (x) + \frac{1}{2} e^{x}

\int sin (3 θ) cos (2 θ) d θ

\frac{d y}{d x} = \frac{3 sec ( y )}{( x + 5 ) ^{2}}

What is laplacetransform-7(t-4) ?
The answer to laplacetransform-7(t-4) is -7/(s^2)+(28)/s