What is the derivative of x+e^x ?

The derivative of x+e^x is 1+e^x

What is the first derivative of x+e^x ?

The first derivative of x+e^x is 1+e^x

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\frac{d}{d x} (x + e^{x})

1 + e^{x}

Solution steps

\frac{d}{d x} (x + e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (e^{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 1 + e^{x}

\frac{\partial}{\partial x} (\frac{y}{2 x ^{2}})

\frac{d}{d x} (\frac{1}{arccos ( 3 x )})

\int x^{2} cos (y) d y

\int \frac{2}{y} d y

3 x^{5} x