What is the derivative of-(x-3^2) ?

The derivative of-(x-3^2) is -2x+6

What is the first derivative of-(x-3^2) ?

The first derivative of-(x-3^2) is -2x+6

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\frac{d}{d x} (- (x - 3)^{2})

- 2 x + 6

Solution steps

\frac{d}{d x} (- (x - 3)^{2})

Simplify

- (x - 3)^{2} : - x^{2} + 6 x - 9

= \frac{d}{d x} (- x^{2} + 6 x - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x) - \frac{d}{d x} (9)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (9) = 0

= - 2 x + 6 - 0

Simplify

= - 2 x + 6

\frac{d}{d x} (- x csc^{2} (x))

n = 1 \sum \infty \frac{3}{e ^{n}}

\int \frac{1}{x ^{2} + 2 x + 10} d x

\int x (2 + x^{2})^{3} d x

\frac{- a - b}{( s + 1 )}

What is the derivative of-(x-3^2) ?
The derivative of-(x-3^2) is -2x+6
What is the first derivative of-(x-3^2) ?
The first derivative of-(x-3^2) is -2x+6