What is (\partial)/(\partial t)(e^{-2t}) ?

The answer to (\partial)/(\partial t)(e^{-2t}) is -2e^{-2t}

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(\partial)/(\partial t)(e^{-2t})

\frac{\partial}{\partial t} (e^{- 2 t})

- 2 e^{- 2 t}

Solution steps

\frac{\partial}{\partial t} (e^{- 2 t})

Apply the chain rule:

e^{- 2 t} \frac{\partial}{\partial t} (- 2 t)

= e^{- 2 t} \frac{\partial}{\partial t} (- 2 t)

\frac{\partial}{\partial t} (- 2 t) = - 2

= e^{- 2 t} (- 2)

Simplify

= - 2 e^{- 2 t}

\int x^{4} - 6 x d x

\frac{d}{d x} (6 e^{x} t + x t)

7 x, 2 x^{2}

\frac{d}{d x} (ln (f (x)) (x))

y^{^{'}} = \frac{sec ( y )}{( x - 1 ) ^{2}}

What is (\partial)/(\partial t)(e^{-2t}) ?
The answer to (\partial)/(\partial t)(e^{-2t}) is -2e^{-2t}