What is the derivative of ln(x^2-8) ?

The derivative of ln(x^2-8) is (2x)/(x^2-8)

What is the first derivative of ln(x^2-8) ?

The first derivative of ln(x^2-8) is (2x)/(x^2-8)

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\frac{d}{d x} (ln (x^{2} - 8))

\frac{2 x}{x ^{2} - 8}

Solution steps

\frac{d}{d x} (ln (x^{2} - 8))

Apply the chain rule:

\frac{1}{x ^{2} - 8} \frac{d}{d x} (x^{2} - 8)

= \frac{1}{x ^{2} - 8} \frac{d}{d x} (x^{2} - 8)

\frac{d}{d x} (x^{2} - 8) = 2 x

= \frac{1}{x ^{2} - 8} \cdot 2 x

Simplify

\frac{1}{x ^{2} - 8} \cdot 2 x : \frac{2 x}{x ^{2} - 8}

= \frac{2 x}{x ^{2} - 8}

\int_{5}^{6} \frac{x}{x ^{2} + 6 x + 13} d x

e^{a x} sin (b x)

x \to 3 lim (e^{\frac{2}{3 - x}})

\frac{\partial}{\partial y} (e^{2 x} cos (y))

\int e^{- x} cos^{2} (x) d x

What is the derivative of ln(x^2-8) ?
The derivative of ln(x^2-8) is (2x)/(x^2-8)
What is the first derivative of ln(x^2-8) ?
The first derivative of ln(x^2-8) is (2x)/(x^2-8)