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Popular >

area y=x^2-4x,y=-x^2

Solution

area

y = x^{2} - 4 x, y = - x^{2}

Solution

\frac{8}{3}

+1

Decimal Notation

2.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} 2 x^{2} - 4 x d x

Solve

\int_{0}^{2} 2 x^{2} - 4 x d x : \frac{8}{3}

The area is:

= \frac{8}{3}

Popular Examples

integral of x^2-3x-4

\int x^{2} - 3 x - 4 d x

limit as x approaches-2+of x/(x^2-3x-10)

x \to - 2 + lim (\frac{x}{x ^{2} - 3 x - 10})

derivative of y= x/(10)-(10)/x derivative of

y = \frac{x}{10} - \frac{10}{x}

integral of ((cos^2(at)))/a

\int \frac{( cos ^{2} ( a t ) )}{a} d x

implicit (dy)/(dx),(7xy+5)^2=42y implicit derivative

\frac{d y}{d x}, (7 x y + 5)^{2} = 42 y

Frequently Asked Questions (FAQ)

What is area y=x^2-4x,y=-x^2 ?
The answer to area y=x^2-4x,y=-x^2 is 8/3