What is the integral from-1 to 2 of (y+2)-y^2 ?

The integral from-1 to 2 of (y+2)-y^2 is 9/2

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integral from-1 to 2 of (y+2)-y^2

\int_{- 1}^{2} (y + 2) - y^{2} d y

\frac{9}{2}

Decimal Notation

4.5

Solution steps

\int_{- 1}^{2} y + 2 - y^{2} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} y d y + \int_{- 1}^{2} 2 d y - \int_{- 1}^{2} y^{2} d y

\int_{- 1}^{2} y d y = \frac{3}{2}

\int_{- 1}^{2} 2 d y = 6

\int_{- 1}^{2} y^{2} d y = 3

= \frac{3}{2} + 6 - 3

Simplify

\frac{3}{2} + 6 - 3 : \frac{9}{2}

= \frac{9}{2}

\int x y e^{x z} d z

\frac{\partial}{\partial z} (e^{c o s (x^{2})})

\int \frac{1}{9 - 16 t ^{2}} d t

\frac{4 x}{x ^{2} + 4}

x \to 2 + lim (ln (x - 2))

What is the integral from-1 to 2 of (y+2)-y^2 ?
The integral from-1 to 2 of (y+2)-y^2 is 9/2