What is the derivative of y+x ?

The derivative of y+x is (dy)/(dx)+1

What is the first derivative of y+x ?

The first derivative of y+x is (dy)/(dx)+1

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\frac{d}{d x} (y + x)

\frac{d y}{d x} + 1

Solution steps

\frac{d}{d x} (y + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d y}{d x} + \frac{d x}{d x}

\frac{d x}{d x} = 1

= \frac{d y}{d x} + 1

x \to 0 lim (5 x^{3} + 2 x)

e^{x} y \frac{d y}{d x} = e^{- y} + e^{- 6 x - y}

\int \frac{1}{( x - 1 ) ^{2} - 4} d x

\frac{d}{d x} (6 x ln (x) + 5 x)

f (x) = 2 x^{4} - 4 x^{2} + 6, at x = - 2

What is the derivative of y+x ?
The derivative of y+x is (dy)/(dx)+1
What is the first derivative of y+x ?
The first derivative of y+x is (dy)/(dx)+1