What is implicit 4x^2+4x+xy=4 ?

The answer to implicit 4x^2+4x+xy=4 is (dy}{dx}=\frac{-8x-y-4)/x

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implicit 4x^2+4x+xy=4

implicit derivative

4 x^{2} + 4 x + x y = 4

\frac{d y}{d x} = \frac{- 8 x - y - 4}{x}

Solution steps

4 x^{2} + 4 x + x y = 4

Treat

y

y (x)

Differentiate both sides:

8 x + 4 + y + x \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- 8 x - y - 4}{x}

\frac{d y}{d x} = \frac{- 8 x - y - 4}{x}

n \to \infty lim (1000 (1.06)^{n})

y^{^{''}} + y = 0, y (\frac{π}{3}) = 4, y^{^{'}} (\frac{π}{3}) = - 8

e^{x}, e^{- 4 x}, [0, ln (4)]

f (x) = 5 x^{3} - 5 x, at x = 1

\frac{d}{d x} (e^{3 - x^{2}})

What is implicit 4x^2+4x+xy=4 ?
The answer to implicit 4x^2+4x+xy=4 is (dy}{dx}=\frac{-8x-y-4)/x