What is the solution for y^'=((6x^4+y^4))/(xy^3) ?

The solution for y^'=((6x^4+y^4))/(xy^3) is y=x\sqrt[4]{24ln(x)+c_{1}},y=-x\sqrt[4]{24ln(x)+c_{1}}

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y^'=((6x^4+y^4))/(xy^3)

y^{^{'}} = \frac{( 6 x ^{4} + y ^{4} )}{x y ^{3}}

Solution steps

y^{'} (x) = \frac{( 6 x ^{4} + y ^{4} )}{x y ^{3}}

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What is the solution for y^'=((6x^4+y^4))/(xy^3) ?
The solution for y^'=((6x^4+y^4))/(xy^3) is y=x\sqrt[4]{24ln(x)+c_{1}},y=-x\sqrt[4]{24ln(x)+c_{1}}